Question

Дано mSO2 = 1,28г Найти: n ? V? N?

Answer 1

N=m/M=1,28/64=0.02 V=Vm⋅n=22.4⋅0.02=0.448
N=V/Vm=0.448/22.4=0.02

Answer 2

Finding the Values of n, V, and N

Given: mSO2 = 1.28g

To find: n, V, N

Solution

The given information is the mass of sulfur dioxide, mSO2 = 1.28g.

We can use the molar mass of sulfur dioxide (SO2) to find the values of n, V, and N.

The molar mass of SO2 is calculated as follows: Molar mass of S = 32.07 g/mol Molar mass of O = 16.00 g/mol Molar mass of SO2 = 32.07 + 2 * 16.00 = 64.07 g/mol

Using the given mass of SO2, we can calculate the number of moles (n) using the formula: n = m / M where: n = number of moles m = mass M = molar mass

Substituting the given values: n = 1.28g / 64.07 g/mol n = 0.02 mol

So, the number of moles (n) of SO2 is 0.02 mol.

Next, we can calculate the volume (V) occupied by the SO2 gas at a certain temperature and pressure using the ideal gas law: PV = nRT where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature

Finally, the Avogadro's number (N) can be calculated using the relationship between the number of moles and the Avogadro's number: N = n * NA where: N = number of particles n = number of moles NA = Avogadro's number (6.022 x 10^23 mol^-1)

These calculations will provide the values of V and N based on the given number of moles of SO2.

Conclusion

The number of moles (n) of SO2 is 0.02 mol. The volume (V) and the Avogadro's number (N) can be calculated using the ideal gas law and the relationship between moles and particles, respectively.