Question

По уравнению химической реакции S+O2 --> SO2 вычислить массу оксида серы(IV), если сгорела 1.6г

Answer 1

N(S)=m/M=1,6/32=0,05 моль
n(S)=n(SO2)
m(SO2)=n*M=0,05*64=3,2 г
Дано
m(S)=1,6 г
m(SO2)-?

Answer 2

Calculating the Mass of Sulfur Dioxide (SO2) Produced

To calculate the mass of sulfur dioxide (SO2) produced when 1.6g of sulfur reacts with oxygen, we can use the balanced chemical equation for the reaction:

S + O2 → SO2

The balanced equation tells us that 1 mole of sulfur reacts with 1 mole of oxygen to produce 1 mole of sulfur dioxide.

Step 1: Calculate the Molar Mass of Sulfur (S)

The molar mass of sulfur (S) is approximately 32.07 g/mol.

Step 2: Calculate the Molar Mass of Sulfur Dioxide (SO2)

The molar mass of sulfur dioxide (SO2) can be calculated by adding the molar masses of sulfur and oxygen together. The molar mass of sulfur is approximately 32.07 g/mol, and the molar mass of oxygen is approximately 16.00 g/mol. Therefore, the molar mass of SO2 is:

32.07 g/mol (S) + 2 * 16.00 g/mol (O) = 64.07 g/mol

Step 3: Calculate the Number of Moles of Sulfur (S)

To find the number of moles of sulfur, we can use the given mass of sulfur (1.6g) and its molar mass:

Number of moles = Mass / Molar mass

Number of moles = 1.6g / 32.07 g/mol ≈ 0.05 moles

Step 4: Use the Stoichiometry of the Reaction

From the balanced chemical equation, we know that 1 mole of sulfur reacts with 1 mole of oxygen to produce 1 mole of sulfur dioxide.

Since the reaction produces 1 mole of SO2 for every mole of S, the number of moles of SO2 produced will also be approximately 0.05 moles.

Step 5: Calculate the Mass of Sulfur Dioxide (SO2) Produced

Finally, we can calculate the mass of sulfur dioxide produced using the number of moles of SO2 and its molar mass:

Mass = Number of moles * Molar mass

Mass = 0.05 moles * 64.07 g/mol ≈ 3.20g

Therefore, the mass of sulfur dioxide (SO2) produced when 1.6g of sulfur reacts with oxygen is approximately 3.20 grams.