Question

Помогите, Дано: m(CxHyOz) = 12г M(CO2) = 0,4моль m(H2O) = 7,2г D(CO2) = 1,875г м.ф - ?

Answer 1

М-это молярная масса, она не может быть 0,4 моль. Может быть это n- количество вещества?

Answer 2

Given Information

The given information is as follows: - m(CxHyOz) = 12g - M(CO2) = 0.4mol - m(H2O) = 7.2g - D(CO2) = 1.875g

Calculating the Molecular Formula

To calculate the molecular formula (m.f) of the compound, we can use the given masses and molar masses of the elements to find the values of x, y, and z in the compound CxHyOz.

First, we need to find the moles of CO2 and H2O using their molar masses: - Molar mass of CO2 (M(CO2)) = 44g/mol - Molar mass of H2O = 18g/mol

Using the given masses, we can calculate the moles of CO2 and H2O: - Moles of CO2 = D(CO2) / M(CO2) = 1.875g / 44g/mol = 0.0426mol - Moles of H2O = m(H2O) / Molar mass of H2O = 7.2g / 18g/mol = 0.4mol

Now, we can use the moles of CO2 and H2O to find the values of x, y, and z in the compound CxHyOz.

Calculating the Values of x, y, and z

The balanced chemical equation for the combustion of a hydrocarbon in oxygen is: CxHyOz + O2 → x CO2 + 0.5y H2O

From the given information, we have: - Moles of CO2 (x) = 0.0426mol - Moles of H2O (0.5y) = 0.4mol

By comparing the coefficients in the balanced chemical equation, we can determine the values of x and y.

Final Result

The values of x and y can be calculated as follows: - x = 0.0426 - y = 0.4 / 0.5 = 0.8

Therefore, the molecular formula (m.f) of the compound CxHyOz is C0.0426H0.8Oz.