Question

Сколько граммов этанола образуется при спиртовом брожении 360 г глюкозы, если выход спирта составляет 65 %?

Answer 1

Решение:
C₆H₁₂O₆-[дрожжи]-->2C₂H₅OH+2CO₂
M(C₆H₁₂O₆)=180г/моль
n(C₆H₁₂O₆)=m/M=360/180=2моль
n(C₂H₅OH)=2*n(C₆H₁₂O₆)=2*2=4моль
M(C₂H₅OH)=46г/моль
m(C₂H₅OH)=n*M=4*46=184г
С выхода:
m(C₂H₅OH)=184*0.65=119.6г
Ответ:119.6г

Answer 2

Calculating Ethanol Production from Glucose Fermentation

To calculate the amount of ethanol produced from the fermentation of 360g of glucose with a 65% ethanol yield, we can use the following formula:

Ethanol produced (in grams) = Glucose amount (in grams) * Ethanol yield percentage

Substituting the given values: Ethanol produced = 360g * 65%

Calculation

Using the formula, the calculation is as follows: Ethanol produced = 360g * 65% = 360g * 0.65 = 234g

Therefore, approximately 234 grams of ethanol are produced from the fermentation of 360 grams of glucose with a 65% ethanol yield.