Question

при взаимодействии углерода с концентрированной серной кислотой выделилось 134,4 л. газов (н.у.), чему равна масса вступившего в реакцию углерода?

Answer 1

C + 2H2SO4 = CO2 + 2SO2 + 2H2O
n ( газов) = 134,4/22,4 = 6 моль т.к.(н.у)
по уравнению 
C              CO2 + SO2
1моль        3 моль
х моль       6моль
n(C) = 2моль
m(C) = 2 * 12 = 24 u

Answer 2

C + 2H2SO4 --> CO2 + 2SO2 + 2H2O 
кол-во в-ва газов = 134,4/22,4= 6 моль
По уравнению выделилось 3V газов. 6/3=2
2 моль - СO2 и 4 моль SO2
кол-во в-ва(С)=кол-во в-ва(СО2)= 2 моль
m(C)=2*12=24 г

Answer 3

Reaction of Carbon with Concentrated Sulfuric Acid

When carbon reacts with concentrated sulfuric acid, a gas is produced. The volume of the gas produced can be used to calculate the mass of the carbon that participated in the reaction.

Calculation of Carbon Mass

The volume of the gas produced is given as 134.4 L at standard conditions. To calculate the mass of the carbon that reacted, we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Given that the gas is at standard conditions (0°C and 1 atm), the ideal gas constant R is 0.0821 L·atm/(K·mol). We can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Using the molar volume of a gas at standard conditions (22.4 L/mol), we can calculate the number of moles of the gas produced. Then, we can use the balanced chemical equation for the reaction to determine the moles of carbon involved and finally calculate the mass of the carbon.

Conclusion

By using the ideal gas law and the balanced chemical equation for the reaction, we can determine the mass of the carbon that participated in the reaction with concentrated sulfuric acid.