Question

.Оксид углерода(IV) прореагировал с оксидом кальция массой 504 грамма. Найдите массу образовавшейся соли.

Answer 1

              504г

CO₂ + CaO          ⇒  CaCO₃

            56г/моль      100г/моль

 

 

 

 

 кол-во вещества CaO = 504г / 56г/моль = 9 моль

у оксида и соли коэффициенты одинаковые, значит, кол-во в-ва одинаковое тоже

масса соли = 9моль* 100г/моль = 900 г

Answer 2

Reaction of Carbon(IV) Oxide with Calcium Oxide

When carbon(IV) oxide (CO2) reacts with calcium oxide (CaO), it forms calcium carbonate (CaCO3). The balanced chemical equation for this reaction is:

2CO2 + 2CaO → 2CaCO3

Given that the mass of the calcium oxide is 504 grams, we can calculate the mass of the formed salt, calcium carbonate.

Using the molar masses: - CO2: 44.01 g/mol - CaO: 56.08 g/mol - CaCO3: 100.09 g/mol

We can calculate the mass of calcium carbonate formed using the stoichiometry of the reaction.

The molar ratio of CO2 to CaCO3 is 2:2, so the mass ratio is also 2:2. Therefore, the mass of the formed calcium carbonate is equal to the mass of the calcium oxide used in the reaction, which is 504 grams.

The mass of the formed salt, calcium carbonate, is 504 grams.