Question

Напишите молекулярные уравнения получения солей ((NH4)2CO3; Mn2S3; Al2(PO4)3) из соответствующих кислот и оснований. определите заряды основного и кислотного остатков для солей.

Answer 1

2NH4OH+H2CO3=(NH4)2CO3 + 2H2O
2Mn(OH)3+3H2S=Mn2S3+6H2O
3Al(OH)3+2H3PO4=Al3(PO4)2 + 6H2O

заряды кислотных остаковCO₃²⁻    S²⁻   PO₄³⁻

Answer 2

Molecular Equations for the Formation of Salts

To determine the molecular equations for the formation of salts, we need to identify the corresponding acids and bases involved. Here are the molecular equations for the formation of the salts (NH4)2CO3, Mn2S3, and Al2(PO4)3:

1. Formation of (NH4)2CO3: - Acid: H2CO3 (carbonic acid) - Base: 2NH3 (ammonia) - Molecular Equation: H2CO3 + 2NH3 → (NH4)2CO3

2. Formation of Mn2S3: - Acid: H2S (hydrogen sulfide) - Base: 3Mn(OH)2 (manganese hydroxide) - Molecular Equation: 3H2S + 2Mn(OH)2 → Mn2S3 + 6H2O

3. Formation of Al2(PO4)3: - Acid: H3PO4 (phosphoric acid) - Base: 2Al(OH)3 (aluminum hydroxide) - Molecular Equation: 2H3PO4 + 3Al(OH)3 → Al2(PO4)3 + 6H2O

Charges of Acidic and Basic Residues in Salts

To determine the charges of the acidic and basic residues in the salts, we need to consider the charges of the ions involved. Here are the charges of the acidic and basic residues for the salts mentioned:

1. (NH4)2CO3: - The acidic residue is (NH4)+, which is derived from the ammonium ion (NH4+). - The basic residue is CO3^2-, which is derived from the carbonate ion (CO3^2-).

2. Mn2S3: - The acidic residue is Mn^2+, which is derived from the manganese(II) ion (Mn^2+). - The basic residue is S^2-, which is derived from the sulfide ion (S^2-).

3. Al2(PO4)3: - The acidic residue is Al^3+, which is derived from the aluminum(III) ion (Al^3+). - The basic residue is PO4^3-, which is derived from the phosphate ion (PO4^3-).

It's important to note that the charges of the acidic and basic residues in salts are determined by the charges of the ions involved in the reaction.

I hope this helps! Let me know if you have any further questions.