Question

Определите колличество молекул воды , которые получится при сгорании 6г водорода

Answer 1

2Н2 + О2 = 2Н2О
4                    2*18
находим массу Н2О = 6*36/4 =54г
находим количество вещества Н2О = 54/18 = 3моль
находим  количество молекул Н2О = 3моль * 6,02 * 10 в 23 степени= 18,06* 10 в 23 степени
 

Answer 2

 6 г                                    Х г

    2H2       +       O2      =      2H2O

n = 2 моль                            n = 2 моль

М = 2 г/моль                       М = 18 г/моль

m = 4 г                m = 36 г

6 г Н2  -  Хг Н2О

4 г Н2  -   36г Н2О

m(H2O) = 6 * 36/4 = 54г

Answer 3

Calculating the Number of Water Molecules from the Combustion of Hydrogen

To determine the number of water molecules produced from the combustion of 6g of hydrogen, we can use the following steps:

1. Determine the moles of hydrogen: Convert the mass of hydrogen to moles. 2. Use the stoichiometry of the reaction: The balanced chemical equation for the combustion of hydrogen can be used to relate the moles of hydrogen to the moles of water. 3. Convert moles of water to molecules: Finally, convert the moles of water to the number of water molecules.

Step 1: Determine the Moles of Hydrogen

The molar mass of hydrogen (H2) is approximately 2 g/mol.

Using the formula: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \]

We can calculate the moles of hydrogen: \[ \text{moles of hydrogen} = \frac{6 \text{ g}}{2 \text{ g/mol}} = 3 \text{ moles} \]

Step 2: Use the Stoichiometry of the Reaction

The balanced chemical equation for the combustion of hydrogen is: \[ 2 \text{ H}_2 + \text{O}_2 \rightarrow 2 \text{ H}_2\text{O} \]

This equation shows that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

Step 3: Convert Moles of Water to Molecules

Since 2 moles of water contain Avogadro's number of molecules (approximately \(6.022 \times 10^{23}\) molecules), we can calculate the number of water molecules produced:

\[ \text{Number of water molecules} = 2 \times 3 \times 6.022 \times 10^{23} = 36.132 \times 10^{23} \text{ molecules} \]

Therefore, the combustion of 6g of hydrogen will produce approximately 36.132 × 10^23 water molecules.