Question

какая масса соли образуется при взаимодействии 104гр алюминия с серной кислотой?

Answer 1

2Al + 3H2SO4 = Al2(SO4)3 + 3H2
1) Из условия:
n(Al)= 104г/27(г/моль) = 3,85 моль
2) Из уравнения:
n(Al2(SO4)3)= 0.5n(Al) = 3.85*0.5= 1. 925 моль
m(Al2(SO4)3) =1.925 моль * 342 (г/моль) = 658,35 г

Answer 2

Calculation of the Mass of Salt Formed

To determine the mass of salt formed when 104 grams of aluminum reacts with sulfuric acid, we need to consider the balanced chemical equation for the reaction. The balanced equation for the reaction between aluminum and sulfuric acid is as follows:

2Al + 3H2SO4 -> Al2(SO4)3 + 3H2

From the balanced equation, we can see that 2 moles of aluminum react with 3 moles of sulfuric acid to produce 1 mole of aluminum sulfate.

To calculate the mass of aluminum sulfate formed, we need to convert the mass of aluminum to moles using its molar mass and then use the mole ratio from the balanced equation to determine the moles of aluminum sulfate formed. Finally, we can convert the moles of aluminum sulfate to grams using its molar mass.

Let's calculate the mass of salt formed step by step:

1. Calculate the moles of aluminum: - The molar mass of aluminum (Al) is 26.98 g/mol. - Moles of aluminum = mass of aluminum / molar mass of aluminum - Moles of aluminum = 104 g / 26.98 g/mol = 3.85 mol

2. Use the mole ratio from the balanced equation to determine the moles of aluminum sulfate formed: - From the balanced equation, we know that 2 moles of aluminum react to form 1 mole of aluminum sulfate. - Moles of aluminum sulfate = (moles of aluminum) / 2 - Moles of aluminum sulfate = 3.85 mol / 2 = 1.93 mol

3. Calculate the mass of aluminum sulfate formed: - The molar mass of aluminum sulfate (Al2(SO4)3) is 342.15 g/mol. - Mass of aluminum sulfate = moles of aluminum sulfate * molar mass of aluminum sulfate - Mass of aluminum sulfate = 1.93 mol * 342.15 g/mol = 660.80 g

Therefore, when 104 grams of aluminum reacts with sulfuric acid, approximately 660.80 grams of aluminum sulfate is formed.

Please note that the above calculation assumes the reaction goes to completion and there are no other side reactions or factors affecting the yield of the reaction.