Question

Какой объём углекислого газа выделится если подействовать соляной кислотой на 10 %-ый раствор карбоната натрия,массой 292 г. Помогите пожалуйста,заранее спасибо.

Answer 1

 

Na2CO3 + 2HCl = 2NaCl + H2O + CO2

 

1/ Найдем массу чистого карбоната = 292*0,1 = 29,2г

кол-во карбоната = 29,2 / 106=0,275 моль

кол-во угл газ = кол-ву крабоната = 0,275 моль

 

объем газа = 0,275 * 22,4=6,16 л

Answer 2

Calculating the Volume of Carbon Dioxide Released

To calculate the volume of carbon dioxide released when hydrochloric acid reacts with a 10% solution of sodium carbonate, we can use the balanced chemical equation for the reaction and the given mass of sodium carbonate.

The balanced chemical equation for the reaction is: 2HCl + Na2CO3 → 2NaCl + H2O + CO2

The molar mass of sodium carbonate (Na2CO3) is 105.99 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol.

Given: - Mass of sodium carbonate (Na2CO3) = 292 g - Concentration of sodium carbonate solution = 10%

Using the molar mass of sodium carbonate, we can calculate the number of moles of sodium carbonate present in the given mass.

Calculation Steps

1. Calculate the number of moles of sodium carbonate: - Number of moles = (mass of Na2CO3) / (molar mass of Na2CO3)

2. Use the stoichiometry of the balanced chemical equation to find the number of moles of carbon dioxide produced.

3. Convert the moles of carbon dioxide to volume using the ideal gas law.

Let's proceed with the calculations.

Calculation

1. Number of moles of sodium carbonate: - Number of moles = 292 g / 105.99 g/mol - Number of moles ≈ 2.75 mol

2. According to the balanced chemical equation, 1 mole of sodium carbonate produces 1 mole of carbon dioxide. - Therefore, the number of moles of carbon dioxide produced = 2.75 mol

3. Using the ideal gas law, we can calculate the volume of carbon dioxide at standard temperature and pressure (STP): - Volume of gas (V) = nRT/P - Where: - n = number of moles - R = ideal gas constant (0.0821 L.atm/mol.K) - T = temperature in Kelvin (273.15 K at STP) - P = pressure in atmospheres (1 atm at STP)

- Volume of carbon dioxide = (2.75 mol) * (0.0821 L.atm/mol.K) * (273.15 K) / (1 atm) - Volume of carbon dioxide ≈ 60.3 L

Conclusion

When hydrochloric acid reacts with a 10% solution of sodium carbonate with a mass of 292 g, approximately 60.3 liters of carbon dioxide gas will be released.

I hope this helps! If you have any further questions, feel free to ask.