
помогите пожалуйста решить по химии задание,мы в классе делали вот пример решения:Zn O=2-2=0,и над
Zn написано +2,а над кислородом -2,вот это мне решите пожалуйста..........:Na2S,CrCl2,Mg3N,CaCl2,MgO2,CaC2,HCLO4,H 3ASo4,HPO3

Ответы на вопрос

Na2S - (Na+) S(2-)
CrCl2 - Cr(3+) Cl(-)
Mg3N - не поняла, что это
CaCl2 - Ca(2+) Cl(-)
MgO - Mg(2+) O(2-)
CaC2 - Ca (2+) C(-)
HCLO4 - H(+) Cl (7-)O4(2-)
H3AsO4 - H3(+) As (5-) O4(2-)
HPO3 - H(+) P(5-) O3(2-)



1. Na2S Na = +1 (group 1A element) S = -2 (group 6A element) Therefore, the oxidation state of Na in Na2S is +1, and the oxidation state of S is -2.
2. CrCl2 Cr = +2 (from the rule that the sum of oxidation states in a compound is equal to zero) Cl = -1 (group 7A element) Therefore, the oxidation state of Cr in CrCl2 is +2, and the oxidation state of Cl is -1.
3. Mg3N Mg = +2 (group 2A element) N = -3 (group 5A element) Therefore, the oxidation state of Mg in Mg3N is +2, and the oxidation state of N is -3.
4. CaCl2 Ca = +2 (group 2A element) Cl = -1 (group 7A element) Therefore, the oxidation state of Ca in CaCl2 is +2, and the oxidation state of Cl is -1.
5. MgO2 Mg = +2 (group 2A element) O = -2 (group 6A element) Therefore, the oxidation state of Mg in MgO2 is +2, and the oxidation state of O is -2.
6. CaC2 Ca = +2 (group 2A element) C = -2 (group 4A element) Therefore, the oxidation state of Ca in CaC2 is +2, and the oxidation state of C is -2.
7. HClO4 H = +1 (group 1A element) Cl = +7 (from the rule that the sum of oxidation states in a compound is equal to zero) O = -2 (group 6A element) Therefore, the oxidation state of H in HClO4 is +1, the oxidation state of Cl is +7, and the oxidation state of O is -2.
8. H3AsO4 H = +1 (group 1A element) As = +5 (from the rule that the sum of oxidation states in a compound is equal to zero) O = -2 (group 6A element) Therefore, the oxidation state of H in H3AsO4 is +1, the oxidation state of As is +5, and the oxidation state of O is -2.
9. HPO3 H = +1 (group 1A element) P = +3 (from the rule that the sum of oxidation states in a compound is equal to zero) O = -2 (group 6A element) Therefore, the oxidation state of H in HPO3 is +1, the oxidation state of P is +3, and the oxidation state of O is -2.


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