Question

Вычислите массу хлорида алюминия,которую можно получить взаимодействием алюминия с 21,3 г хлора Прошу срочно надо

Answer 1

В приложении решение к задаче

Answer 2

Calculation of the Mass of Aluminum Chloride

To calculate the mass of aluminum chloride (AlCl3) that can be obtained from the reaction between aluminum and 21.3 grams of chlorine (Cl2), we need to consider the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between aluminum and chlorine is:

2 Al + 3 Cl2 → 2 AlCl3

From the balanced equation, we can see that 2 moles of aluminum react with 3 moles of chlorine to produce 2 moles of aluminum chloride.

To calculate the mass of aluminum chloride, we need to determine the number of moles of chlorine present in 21.3 grams of chlorine. We can use the molar mass of chlorine to convert grams to moles.

The molar mass of chlorine (Cl2) is approximately 70.91 grams/mol.

Using the formula:

Number of moles = Mass / Molar mass

We can calculate the number of moles of chlorine:

Number of moles of chlorine = 21.3 g / 70.91 g/mol

Now, we can use the mole ratio from the balanced equation to determine the number of moles of aluminum chloride produced.

From the balanced equation, we know that 3 moles of chlorine react to produce 2 moles of aluminum chloride.

Number of moles of aluminum chloride = (Number of moles of chlorine) * (2 moles of AlCl3 / 3 moles of Cl2)

Finally, we can calculate the mass of aluminum chloride using the molar mass of aluminum chloride.

The molar mass of aluminum chloride (AlCl3) is approximately 133.34 grams/mol.

Mass of aluminum chloride = (Number of moles of aluminum chloride) * (Molar mass of AlCl3)

Let's calculate the mass of aluminum chloride:

Number of moles of chlorine = 21.3 g / 70.91 g/mol = 0.2996 mol

Number of moles of aluminum chloride = 0.2996 mol * (2 mol AlCl3 / 3 mol Cl2) = 0.1997 mol

Mass of aluminum chloride = 0.1997 mol * 133.34 g/mol = 26.63 grams

Therefore, the mass of aluminum chloride that can be obtained from the reaction between aluminum and 21.3 grams of chlorine is approximately 26.63 grams.