Question

На основании объемных отношений газов определите ,какой объем (н.у.) ацетилена сгорает ,если образуется оксид углерода4 объемом 20 литров.Реакция горения ацителена 2С2H2+5О2=4CO2+2H2O

Answer 1

Решение:
2C₂H₂+5O₂--->4CO₂+2H₂O
Иcходя из пропорции:
$V(C_{2}H_{2})= \frac{V(CO_{2})*2 }{4}= \frac{20*2}{4}=10$л
Ответ: 10л.

Answer 2

Calculation of the Volume of Acetylene Burned

To determine the volume of acetylene burned, we can use the stoichiometry of the combustion reaction and the given volume of carbon dioxide produced.

The balanced equation for the combustion of acetylene (C2H2) is:

2C2H2 + 5O2 → 4CO2 + 2H2O

According to the stoichiometry of the reaction, for every 2 moles of acetylene burned, 4 moles of carbon dioxide are produced. This means that the molar ratio of acetylene to carbon dioxide is 2:4, or 1:2.

Given that the volume of carbon dioxide produced is 20 liters, we can use the molar volume of gases at standard temperature and pressure (STP) to calculate the volume of acetylene burned.

At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, if we know the volume of one gas, we can calculate the number of moles of that gas and then use the stoichiometry of the reaction to determine the number of moles of the other gas.

Let's calculate the number of moles of carbon dioxide produced:

Volume of carbon dioxide = 20 liters Molar volume of gases at STP = 22.4 liters/mol

Number of moles of carbon dioxide = Volume of carbon dioxide / Molar volume of gases at STP Number of moles of carbon dioxide = 20 liters / 22.4 liters/mol

Now, using the stoichiometry of the reaction, we can determine the number of moles of acetylene burned:

Number of moles of acetylene = (Number of moles of carbon dioxide) / 2

Finally, we can calculate the volume of acetylene burned using the molar volume of gases at STP:

Volume of acetylene burned = Number of moles of acetylene * Molar volume of gases at STP

Let's perform the calculations:

Number of moles of carbon dioxide = 20 liters / 22.4 liters/mol = 0.8929 mol Number of moles of acetylene = 0.8929 mol / 2 = 0.4465 mol Volume of acetylene burned = 0.4465 mol * 22.4 liters/mol = 9.99 liters (approximately)

Therefore, approximately 9.99 liters of acetylene will be burned if 20 liters of carbon dioxide are produced during the combustion reaction.

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