Question

химия очень нужна помощь!!!!!!!!!!!!Вычислите массу глюкозы,если в результате ее окисления выделилось 4096,4 кДжС6H12O6+6O2=6CO2+6H2O+2926 кДжответ 252г

Answer 1

С6H12O6+6O2=6CO2+6H2O+2926 кДж

1моль-2926 кДЖ

х моль-4096,4 кДЖ

х=1,4моль

m(С6H12O6)=v*M=1,4*180=252г

Answer 2

Calculation of Glucose Mass

To calculate the mass of glucose, we need to use the balanced equation for the oxidation of glucose:

C6H12O6 + 6O2 → 6CO2 + 6H2O

According to the given information, the energy released during the oxidation of glucose is 4096.4 kJ. We also know that the energy released per mole of glucose is 2926 kJ.

To find the mass of glucose, we can use the following steps:

1. Calculate the number of moles of glucose using the energy released per mole: - Moles of glucose = Energy released / Energy released per mole - Moles of glucose = 4096.4 kJ / 2926 kJ/mol

2. Convert the moles of glucose to grams using the molar mass of glucose: - Molar mass of glucose (C6H12O6) = (6 * atomic mass of carbon) + (12 * atomic mass of hydrogen) + (6 * atomic mass of oxygen) - Molar mass of glucose = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)

3. Calculate the mass of glucose: - Mass of glucose = Moles of glucose * Molar mass of glucose

Let's calculate the mass of glucose using these steps:

1. Moles of glucose = 4096.4 kJ / 2926 kJ/mol = 1.401 mol 2. Molar mass of glucose = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol) = 180.18 g/mol 3. Mass of glucose = 1.401 mol * 180.18 g/mol = 252 g

Therefore, the mass of glucose is 252 grams.