Question

al2(so4)3+6naoh-2al(oh)3=3na2so4 написать сокрашонное ионное уравнение!!!

Answer 1

2Al³⁺ + 3SO₄²⁻ + 6Na⁺ + 6OH⁻ = 6Na⁺ 3SO₄²⁻ +  2Al(OH)3 полное ионное
2Al³⁺ + 6OH⁻ =   2Al(OH)3 сокращенное ионное

Answer 2

Ionic Equation for the Reaction of Al2(SO4)3 and 6NaOH to Produce 2Al(OH)3 and 3Na2SO4

The ionic equation for the reaction of Al2(SO4)3 and 6NaOH to produce 2Al(OH)3 and 3Na2SO4 involves the dissociation of the compounds into their respective ions and the subsequent recombination to form the products. Here's the ionic equation for this reaction:

Step 1: Dissociation of Al2(SO4)3 and 6NaOH - Al2(SO4)3 dissociates into ions as follows: - Al2(SO4)3 → 2Al^3+ + 3SO4^2- - 6NaOH dissociates into ions as follows: - 6NaOH → 6Na^+ + 6OH^-

Step 2: Recombination to Form 2Al(OH)3 and 3Na2SO4 - The aluminum ions (Al^3+) react with the hydroxide ions (OH^-) to form aluminum hydroxide (Al(OH)3): - 2Al^3+ + 6OH^- → 2Al(OH)3 - The sodium ions (Na^+) and sulfate ions (SO4^2-) recombine to form sodium sulfate (Na2SO4): - 3Na^+ + 3SO4^2- → 3Na2SO4

Overall Ionic Equation: - The overall ionic equation for the reaction can be represented as: - 2Al^3+ + 6OH^- + 6Na^+ + 3SO4^2- → 2Al(OH)3 + 3Na2SO4

This equation represents the dissociation and recombination of ions to form the products 2Al(OH)3 and 3Na2SO4 from the reactants Al2(SO4)3 and 6NaOH.

I hope this helps! If you have any more questions or need further clarification, feel free to ask.