
Составьте уравнения реакций в соответствии со схемой превращений:
C2H4-->C2H5OH-->C2H4-->CO2-->CaCO3--(над стрелкой +H2O,CO2-->X Укажите условия протекания реакций и назовите вещество Х. помогите пожалуйста!

Ответы на вопрос

C2H4-->C2H5OH-->C2H4-->CO2-->CaCO3-->X
1) C2H4 + HOH (150 C, H+) = C2H5OH
2) C2H5OH (H2SO4) = C2H4 + H2O
3) C2H4 + 3O2 = 2CO2 + 2H2O
4) CO2 + CaO = CaCO3
5) CaCO3 + H2CO3 = Ca(HCO3)2



Reaction Equations:
The given scheme of transformations can be represented by the following reaction equations:
1. C2H4 → C2H5OH 2. C2H5OH → C2H4 + CO2 3. CO2 → CaCO3
Conditions and Substance X:
To determine the conditions and substance X, let's analyze each reaction step by step:
1. C2H4 → C2H5OH: - This reaction represents the addition of a hydrogen atom to ethene (C2H4) to form ethanol (C2H5OH). - The reaction is a typical example of an addition reaction, where a double bond is broken and new bonds are formed. - The reaction is catalyzed by a suitable catalyst, such as a transition metal catalyst like platinum (Pt) or palladium (Pd) [[1]].
2. C2H5OH → C2H4 + CO2: - This reaction represents the dehydration of ethanol (C2H5OH) to form ethene (C2H4) and carbon dioxide (CO2). - The reaction occurs under high temperature and in the presence of a suitable catalyst, such as alumina (Al2O3) or silica (SiO2) [[2]].
3. CO2 → CaCO3: - This reaction represents the formation of calcium carbonate (CaCO3) from carbon dioxide (CO2). - The reaction occurs in the presence of water (H2O) and under high pressure. - The reaction is known as carbonation and is commonly observed in natural processes like the formation of limestone [[3]].
Based on the given scheme, the substance X is carbon dioxide (CO2).
Summary:
In summary, the reaction scheme can be represented by the following equations:
1. C2H4 → C2H5OH (catalyzed by Pt or Pd) 2. C2H5OH → C2H4 + CO2 (under high temperature and in the presence of Al2O3 or SiO2) 3. CO2 → CaCO3 (in the presence of H2O and under high pressure)
The substance X in the reaction scheme is carbon dioxide (CO2).
I hope this helps! Let me know if you have any further questions.


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