Question

Рассчитайте, хватит ли 10 л кислорода для полного сжигания 4 л метана

Answer 1

CH4+2O2=CO2+2H2O
кол-во вещества(НЮ)=4л/22,4 л/моль=0,179 моль(CH4)
кол-во вещества(ню)=0,358 моль (O2)
V(O2)=0,358 моль*22,4 л/моль=8,0192 л=примерно 8 л
Следовательно, 10 л кислорода хватит для полного сгорания метана

Answer 2

Calculating Oxygen Needed for Complete Combustion of Methane

To calculate whether 10 L of oxygen is sufficient for the complete combustion of 4 L of methane, we can use the balanced chemical equation for the combustion of methane:

CH4 + 2O2 → CO2 + 2H2O

From the balanced equation, we can see that 1 mole of methane reacts with 2 moles of oxygen. We can use this information to calculate the amount of oxygen needed for the given amount of methane.

Calculation

1. Calculate the moles of methane: - Moles of methane = Volume of methane / molar volume at STP - Moles of methane = 4 L / 22.4 L/mol (molar volume at STP) = 0.1786 moles

2. Calculate the moles of oxygen needed: - Moles of oxygen needed = Moles of methane * 2 (from the balanced equation) - Moles of oxygen needed = 0.1786 moles * 2 = 0.3572 moles

3. Convert moles of oxygen to volume at STP: - Volume of oxygen needed = Moles of oxygen * molar volume at STP - Volume of oxygen needed = 0.3572 moles * 22.4 L/mol = 8.0 L

Conclusion

Based on the calculation, 10 L of oxygen is more than enough for the complete combustion of 4 L of methane, as only approximately 8.0 L of oxygen is needed for the reaction.