Question

Элемент с электронной конфигурацией внешнего уровня .....3s23p3 образует водородное соединение состава 1)ЭН4 2)ЭН3 3)ЭН2 4)ЭН С объяснением, пожалуйста)

Answer 1

Элемент с электронной конфигурацией ...3s²3p³ находится в 3 периоде V группе - это фосфор, он образует летучее водородное соединение - фосфин РН₃, что соответствует второму ответу ЭН₃
Ответ: 2

Answer 2

Electron Configuration and Hydrogen Compounds

The element with the electron configuration of 3s^23p^3 belongs to the group 15 elements in the periodic table, specifically nitrogen (N). Nitrogen has 5 electrons in its outer shell, with 3 in the 2p sublevel and 2 in the 2s sublevel.

When nitrogen forms hydrogen compounds, it typically forms ammonia (NH3), which is the compound with the formula NH3. This is because nitrogen has 3 unpaired electrons in its outer shell, allowing it to form three covalent bonds with hydrogen atoms.

Therefore, the correct answer is 2) NH3. Nitrogen forms a hydrogen compound with the composition of NH3, known as ammonia.

This is based on the chemical properties of nitrogen and the principles of chemical bonding, as well as the electron configuration of nitrogen, which allows it to form multiple covalent bonds with hydrogen atoms.

I hope this explanation helps! If you have further questions or need additional information, feel free to ask.