Question

Дані такі речовини: Al(OH)3, Fe(OH)2, Be(OH)2, H2SiO3. Визначити, скільки з них буде розчинятися і у кислоті, і у лузі. Написати рівняння всіх можливих реакцій.

Answer 1

Объяснение:

ось відповідь (я сама не шарю за хімію)

Answer 2

Solubility of Substances in Acid and Base

To determine the solubility of the given substances in acid and base, we'll first examine the solubility of each substance and then write the equations for the possible reactions in both acid and base.

Al(OH)3: - Solubility in acid: Al(OH)3 will dissolve in acid to form Al3+ ions and water. - Solubility in base: Al(OH)3 will dissolve in base to form Al(OH)4- ions.

Fe(OH)2: - Solubility in acid: Fe(OH)2 will dissolve in acid to form Fe2+ ions and water. - Solubility in base: Fe(OH)2 will not dissolve in base.

Be(OH)2: - Solubility in acid: Be(OH)2 will not dissolve in acid. - Solubility in base: Be(OH)2 will dissolve in base to form Be(OH)4^2- ions.

H2SiO3: - Solubility in acid: H2SiO3 will dissolve in acid to form H4SiO4. - Solubility in base: H2SiO3 will not dissolve in base.

Equations for Possible Reactions

Al(OH)3: - In acid: Al(OH)3 + 3H+ → Al^3+ + 3H2O - In base: Al(OH)3 + OH- → Al(OH)4-

Fe(OH)2: - In acid: Fe(OH)2 + 2H+ → Fe^2+ + 2H2O - In base: No reaction

Be(OH)2: - In acid: No reaction - In base: Be(OH)2 + 2OH- → Be(OH)4^2-

H2SiO3: - In acid: H2SiO3 + 2H+ → H4SiO4 - In base: No reaction

These reactions represent the dissolution of the given substances in acid and base, as well as the formation of respective ions or compounds.