Question

В растворе массой 500 г г. содержится нитрат натрия NaNO3 массой 25 г .Определите массовую долю нитратов натрия в этом растворе

Answer 1

Дано:

m(p-pa NaNO₃)= 500 r

m(NaNO₃) = 25 r

Найти:

ω(NaNO₃) -?

Решение.

ω(NaNO₃) = m(NaNO₃)/m(p-pa NaNO₃) = 25/500 = 0,05 или 5%

Ответ: 5%

Answer 2

W(NaNO3)=m(NaNO3)/m(раствора)=25г/500г=0.05=5%

Answer 3

Calculation of the Mass Fraction of Sodium Nitrate in the Solution

To determine the mass fraction of sodium nitrate (NaNO3) in the solution, we need to compare the mass of sodium nitrate to the total mass of the solution.

Given: - Mass of the solution = 500 g - Mass of sodium nitrate (NaNO3) = 25 g

To calculate the mass fraction, we can use the formula:

Mass Fraction = (Mass of Sodium Nitrate / Mass of Solution) * 100

Substituting the given values into the formula:

Mass Fraction = (25 g / 500 g) * 100

Calculating the mass fraction:

Mass Fraction = 5%

Therefore, the mass fraction of sodium nitrate (NaNO3) in the solution is 5%.