Question

Помагите !!!продукт полученный при взаимодействии 10 л водорода и 28 г растворили в воде объемом 200 мл Рассчитайте массовую долю вещества в полученном растворе

Answer 1

Відповідь:

12.28%

Пояснення:

масса воды равна 200 г ( 1г/мл (плотность) * 200 мл)

масса раствора равна 200 + 28 = 228 г

массовая доля вщества в растворе равна 28/228*100%=12.28%

Answer 2

Calculation of Mass Fraction in the Solution

To calculate the mass fraction of a substance in a solution, we need to know the mass of the substance and the total mass of the solution. In this case, we have 10 liters of hydrogen gas (H2) and 28 grams of a substance dissolved in 200 milliliters of water.

To calculate the mass fraction, we first need to convert the volume of hydrogen gas to its mass. The molar mass of hydrogen gas (H2) is 2 grams/mol. Since we have 10 liters of hydrogen gas, we can calculate the mass using the following equation:

Mass of hydrogen gas = Volume of hydrogen gas × Molar mass of hydrogen gas

Mass of hydrogen gas = 10 liters × 2 grams/mol = 20 grams

Next, we need to calculate the total mass of the solution. We have 28 grams of the substance dissolved in 200 milliliters of water. The density of water is approximately 1 gram/mL. Therefore, the mass of the water is:

Mass of water = Volume of water × Density of water

Mass of water = 200 milliliters × 1 gram/mL = 200 grams

Finally, we can calculate the mass fraction of the substance in the solution using the following equation:

Mass fraction = Mass of substance / Total mass of solution

Mass fraction = 28 grams / (20 grams + 200 grams) = 28 grams / 220 grams ≈ 0.1273

Therefore, the mass fraction of the substance in the solution is approximately 0.1273 or 12.73%.

Please note that the specific substance that was dissolved in the water was not mentioned in the question. If you have any further questions or need clarification, please let me know.