Question

Составь формулу соединения бериллия с фосфором (степень окисления — 3) и вычисли его относительную Молекулярную массу.Ответ: относительная молекулярная масса равнаОтветитьПредыдущее заданиеСписок аданийЯ​

Answer 1

Ответ:

Be3P2

М (Be) =9*3=27 г/моль

М(Р) =31*2=62 г/моль

М (Ве3Р2) =27+62=89 г/моль

Объяснение:

Answer 2

The formula for the compound formed between beryllium and phosphorus with a oxidation state of +3 is BeP2. To calculate its relative molecular mass, we need to consider the atomic masses of beryllium (Be) and phosphorus (P) and multiply them by their respective subscripts in the formula.

The atomic mass of beryllium (Be) is approximately 9.01218 atomic mass units (amu) [[1]]. The atomic mass of phosphorus (P) is approximately 30.97376 amu [[2]].

In the compound BeP2, there are two phosphorus atoms. Therefore, the calculation for the relative molecular mass is as follows:

Relative molecular mass = (Atomic mass of beryllium) + (2 * Atomic mass of phosphorus) = (9.01218 amu) + (2 * 30.97376 amu) = 9.01218 amu + 61.94752 amu = 70.9597 amu

Therefore, the relative molecular mass of the compound BeP2 is approximately 70.9597 amu.

I hope this helps! Let me know if you have any further questions.