Question

Сосчитай сумму коэффициентов в правой части уравнения реакции окислительно-восстановительной реакции, схема которой: Zn+HNO3→Zn(NO3)2+NH4NO3+H2O.

Answer 1

Ответ:

4 Zn + 10 HNO3 → 4 Zn(NO3)2 + NH4NO3 + 3 H2O

Объяснение:

Это окислительно-восстановительная (редокс) реакция:

4 Zn0 - 8 e- → 4 ZnII (окисление)

NV + 8 e- → N-III (восстановле́ние)

Zn является восстановителем, HNO3 является окислителем.

Answer 2

Ответ:

корь корь корь корь корь

Answer 3

Calculation of the Sum of Coefficients in the Right Side of the Redox Reaction Equation

To calculate the sum of coefficients in the right side of the redox reaction equation, we need to balance the equation first. Let's balance the given equation:

Zn + HNO3 → Zn(NO3)2 + NH4NO3 + H2O

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

Zn + 2HNO3 → Zn(NO3)2 + NH4NO3 + H2O

Now, let's calculate the sum of coefficients in the right side of the equation. The right side of the equation consists of Zn(NO3)2, NH4NO3, and H2O.

The coefficients for these compounds are: - Zn(NO3)2: 1 - NH4NO3: 1 - H2O: 1

Therefore, the sum of coefficients in the right side of the equation is 1 + 1 + 1 = 3.

Please note that the coefficients represent the number of moles of each compound involved in the reaction.