Question

Знайти об'єм 5 моль азота​

Answer 1

Ответ:

112(л)

Объяснение:

V=Vm*n=22,4*5=112(л)

Answer 2

Finding the Volume of 5 Moles of Nitrogen

To find the volume of 5 moles of nitrogen, we can use the ideal gas law equation, which is expressed as:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

We can rearrange the equation to solve for volume:

V = (nRT) / P

Now, let's plug in the given values: - n = 5 moles - R = ideal gas constant (approximately 0.0821 L·atm/(K·mol)) - T = temperature (in Kelvin) - P = pressure (if given)

Since the pressure and temperature are not provided, we'll assume standard temperature and pressure (STP) for this calculation: - T = 273.15 K - P = 1 atm

Substituting these values into the equation: V = (5 moles) * (0.0821 L·atm/(K·mol)) * (273.15 K) / 1 atm

Calculation

``` V = (5) * (0.0821) * (273.15) / 1 ≈ 112.5 L ```

So, the volume of 5 moles of nitrogen at standard temperature and pressure is approximately 112.5 liters.