Question

4.Сколько моль Na2CO3 * 10H2O необходимо для приготовления 200 мл раствора соды Na2CO3  концентрацией 0.3 моль/л. Рассчитайте массу соды в граммах. Неправильный ответ сразу в бан.​

Answer 1

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Answer 2

Calculating the Amount of Na2CO3 * 10H2O Needed

To calculate the amount of Na2CO3 * 10H2O needed to prepare a 200 ml solution of Na2CO3 with a concentration of 0.3 mol/L, we can use the formula:

n = c * V

Where: - n = amount of substance in moles - c = concentration in mol/L - V = volume in liters

Substituting the given values: - c = 0.3 mol/L - V = 0.2 L (200 ml = 0.2 L)

We can calculate the amount of substance (n) required.

n = 0.3 mol/L * 0.2 L n = 0.06 moles

So, the amount of Na2CO3 * 10H2O needed to prepare the solution is 0.06 moles.

Calculating the Mass of Na2CO3 in Grams

The molar mass of Na2CO3 * 10H2O can be calculated as follows:

- Molar mass of Na = 22.99 g/mol - Molar mass of C = 12.01 g/mol - Molar mass of O = 16.00 g/mol - Molar mass of H2O = 18.02 g/mol - Molar mass of Na2CO3 * 10H2O = (2*22.99) + 12.01 + (3*16.00) + 10*(18.02) - Molar mass of Na2CO3 * 10H2O = 286.14 g/mol

Now, we can calculate the mass of Na2CO3 * 10H2O needed using the formula:

mass = n * molar mass

Substituting the values: - n = 0.06 moles - molar mass = 286.14 g/mol

We can calculate the mass of Na2CO3 * 10H2O needed.

mass = 0.06 moles * 286.14 g/mol mass ≈ 17.17 grams

Therefore, the mass of Na2CO3 * 10H2O needed to prepare the 200 ml solution of Na2CO3 with a concentration of 0.3 mol/L is approximately 17.17 grams.