Question

На спалювання пропан-пропенової суміші об'ємом 45 л витрачено кисень об'ємом 210 л. Обчисліть об'єм пропану у складі суміші, якщо всі виміри зроблено за однаковиї умов.

Answer 1

Ответ:

Ответ110 литров 111111111

Answer 2

Calculation of Propane Volume in the Mixture

To calculate the volume of propane in the mixture, we can use the concept of stoichiometry and the ideal gas law. Given that the volume of the propane-propene mixture is 45 L and the volume of oxygen consumed is 210 L, we can determine the volume of propane in the mixture.

First, we need to establish the balanced chemical equation for the combustion of propane:

C3H6 + 9/2 O2 → 3 CO2 + 3 H2O

From the balanced equation, we can see that 1 mole of propane (C3H6) reacts with 9/2 moles of oxygen (O2) to produce 3 moles of carbon dioxide (CO2) and 3 moles of water (H2O).

Using the ideal gas law, we can relate the volumes of gases to the number of moles:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Given that the measurements are taken under the same conditions, the pressure, temperature, and gas constant remain constant, allowing us to directly relate the volumes to the number of moles.

Calculation Steps

1. Calculate the number of moles of oxygen consumed. 2. Use the stoichiometry of the reaction to determine the number of moles of propane consumed. 3. Convert the moles of propane to volume using the ideal gas law.

Step 1: Calculate Moles of Oxygen Consumed

The volume of oxygen consumed is 210 L.

Step 2: Determine Moles of Propane Consumed

Using the stoichiometry of the reaction, we can relate the moles of oxygen consumed to the moles of propane consumed.

Step 3: Convert Moles of Propane to Volume

Once we have the moles of propane, we can use the ideal gas law to calculate the volume of propane in the mixture.

Let's proceed with the calculations.