Question

18грамм алюминия растворили в соляной кислоте.Рассчитать массу полченной соли.

Answer 1

2Al+6HCl=2AlCl3+3H2
решаем с помощью пропорции
над Al пишем 18 г(Под 54г-молярная масса),Над AlCl3 х г.(под 160,5)
х=160,5*18/54=53.5 г

Answer 2

Calculating the Mass of the Obtained Salt

To calculate the mass of the obtained salt when 18 grams of aluminum are dissolved in hydrochloric acid, we can use the chemical equation for the reaction between aluminum and hydrochloric acid. The balanced chemical equation for the reaction is:

2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)

From the balanced chemical equation, we can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 2 moles of aluminum chloride. Now, let's calculate the mass of aluminum chloride produced when 18 grams of aluminum are dissolved in hydrochloric acid.

Calculation

1. Calculate the moles of aluminum used: - The molar mass of aluminum (Al) is approximately 26.98 g/mol. - Using the formula: moles = mass / molar mass, we can calculate the moles of aluminum used. - Moles of aluminum = 18 g / 26.98 g/mol = 0.667 moles

2. Calculate the moles of aluminum chloride produced: - From the balanced chemical equation, 2 moles of aluminum produce 2 moles of aluminum chloride. - Therefore, moles of aluminum chloride = 0.667 moles

3. Calculate the mass of aluminum chloride produced: - The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol. - Using the formula: mass = moles * molar mass, we can calculate the mass of aluminum chloride produced. - Mass of aluminum chloride = 0.667 moles * 133.34 g/mol = 88.87 grams

Answer

When 18 grams of aluminum are dissolved in hydrochloric acid, the mass of the obtained salt (aluminum chloride) is approximately 88.87 grams.

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