Question

Какой объем в литрах (н.у) занимает водород , если число молекул составляют 3,01•10²³​

Answer 1

Ответ:

11.2 литра

Объяснение:

Ну смотри:

Число Авогадро = Na = 6.02*$10^{23}$ (Nа - число Авогадро, не путать с натрием). Молекул у тебя = N = 3.01*$10^{23}$. Таким образом, у тебя кол-во моль водорода = кол-во молекул/число Авогадро = N/Na. $\frac{3,01*10^{23} }{6,02*10^{23} } =\frac{3,01}{6,02} =0,5$ моль. 1 моль любого газа при Н.У. занимает 22.4 литра по объёму.

Vm = 22.4 литра на моль, тогда V = Vm*n = 22.4*0.5 = 11.2 литра

Answer 2

Calculating the Volume of Hydrogen Molecules

To calculate the volume of hydrogen in liters (at standard conditions) when the number of molecules is 3.01×10²³, we can use the Avogadro's law, which states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.

The molar volume of a gas at standard temperature and pressure (STP) is 22.4 liters. Therefore, the volume of hydrogen in liters can be calculated using the given number of molecules.

Using Avogadro's law: The molar volume of a gas at STP is 22.4 liters.

Given: Number of molecules = 3.01×10²³

Calculation: Volume of hydrogen = (Number of molecules) × (Molar volume at STP) Volume of hydrogen = 3.01×10²³ × 22.4

Result: Volume of hydrogen = 67.424×10²³ liters

Therefore, the volume of hydrogen, when the number of molecules is 3.01×10²³, is approximately 67.424×10²³ liters.