Question

5. Органiчна речовина масою 5,7 г повністю згоріла в атмосферi кисню. Утворився карбон діоксид масою 15,4 г та вода масою 6,3 г. Густина пари речовини за метаном - 7,125. Знайдіть молекулярну формулу речовини​

Answer 1

Ответ:С7Н14О

Объяснение:

Answer 2

To find the molecular formula of the substance, we need to analyze the given information and calculate the molar masses of the compounds involved.

Given: - Mass of organic substance burned = 5.7 g - Mass of carbon dioxide formed = 15.4 g - Mass of water formed = 6.3 g - Density of the substance vapor compared to methane = 7.125

Let's calculate the number of moles for each compound:

1. Calculate the number of moles of carbon dioxide (CO2): - Molar mass of CO2 = 12.01 g/mol (carbon) + 2 * 16.00 g/mol (oxygen) = 44.01 g/mol - Moles of CO2 = Mass of CO2 / Molar mass of CO2 = 15.4 g / 44.01 g/mol = 0.35 mol

2. Calculate the number of moles of water (H2O): - Molar mass of H2O = 2 * 1.01 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 18.02 g/mol - Moles of H2O = Mass of H2O / Molar mass of H2O = 6.3 g / 18.02 g/mol = 0.35 mol

3. Calculate the number of moles of carbon (C) in the organic substance: - Moles of C = Moles of CO2 = 0.35 mol

4. Calculate the number of moles of hydrogen (H) in the organic substance: - Moles of H = 2 * Moles of H2O = 2 * 0.35 mol = 0.70 mol

5. Calculate the number of moles of oxygen (O) in the organic substance: - Moles of O = Moles of CO2 + Moles of H2O = 0.35 mol + 0.35 mol = 0.70 mol

Now, let's find the empirical formula of the substance by dividing the number of moles of each element by the smallest number of moles (0.35 mol):

- Empirical formula: C0.35H0.70O0.70

To find the molecular formula, we need to know the molar mass of the substance. However, the given information does not provide the molar mass. Without the molar mass, we cannot determine the molecular formula of the substance.

Please provide the molar mass of the substance or any additional information to proceed further.