Question

Задача. Скільки молів Натрій оксиду утвориться при взаємодії 2 молів Натрію з Киснем?Скільки молів Кисню при цьому витратиться?​

Answer 1

Дано:

n(Na) = 2 моль

Знайти:

n(Na2O) - ?

n(O2) - ?

Розв'язання:

1) 4Na + O2 → 2Na2O;

2) n(Na2O) = n(Na) * 2 / 4 = 2 * 2 / 4 = 1 моль;

3) n(O2) = n(Na) / 4 = 2 / 4 = 0,5 моль.

Відповідь: Кількість речовини Na2O становить 1 моль; O2 - 0,5 моль.

Answer 2

Calculation of Sodium Oxide Formation

To determine the number of moles of sodium oxide formed when 2 moles of sodium react with oxygen, we need to consider the balanced chemical equation for the reaction.

The balanced equation for the reaction between sodium and oxygen to form sodium oxide is:

2 Na + O2 -> 2 Na2O

From the balanced equation, we can see that 2 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide.

Therefore, when 2 moles of sodium react with oxygen, 2 moles of sodium oxide will be formed.

Calculation of Oxygen Consumption

To determine the number of moles of oxygen consumed during the reaction, we can use the same balanced chemical equation.

From the balanced equation:

2 Na + O2 -> 2 Na2O

We can see that 2 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide.

Therefore, when 2 moles of sodium react with oxygen, 1 mole of oxygen will be consumed.

So, in summary: - 2 moles of sodium will react with oxygen to form 2 moles of sodium oxide. - During this reaction, 1 mole of oxygen will be consumed.

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