Question

Неизвестный металл массой 13 г полностью прореагировал с бромом,в результате чего образовалось сложное вещество массой 45 г.Определите этот металл,если известно,что в своих соединениях он проявляет валентность,равную двум

Answer 1

Ответ:

за Х мы взяли молярную массу металла

Answer 2

Unknown Metal Reacting with Bromine

To determine the unknown metal that reacted with bromine, we can use the principle of conservation of mass. According to the problem statement, the unknown metal has a mass of 13 g and completely reacted with bromine to form a compound with a mass of 45 g.

Let's assume the unknown metal is represented by the symbol M. The reaction between the metal and bromine can be represented as follows:

M + Br2 → MBrx

Based on the given information, we can set up an equation to solve for the value of x, which represents the valency of the metal:

13 g (mass of M) + 2 * 79.9 g (mass of Br2) = 45 g (mass of MBrx)

Simplifying the equation:

13 g + 159.8 g = 45 g + x * 79.9 g

172.8 g = 45 g + 79.9 g * x

172.8 g - 45 g = 79.9 g * x

127.8 g = 79.9 g * x

x = 127.8 g / 79.9 g

x ≈ 1.6

Since the valency of the metal is given as 2, we can conclude that the metal in question is not the unknown metal.

Unfortunately, the available search results do not provide specific information about the unknown metal that matches the given criteria. It is important to note that the valency of the metal is not consistent with the given information.

If you have any additional information or if there are any other questions I can assist you with, please let me know!