Question

Скласти рівняння реакції взаємодії пропанової кислоти з киснем, калієм та натрій карбонатом ​

Answer 1

Ответ:

2C2H5COOH +6O2 = 4CO2+ 6H2O

2C2H5COOH+2K=2C2H5COOK + H2

2C2H5COOH + NaCO3=C2H5COONA + H2O+CO2

Answer 2

Equation of the reaction between propanoic acid, oxygen, potassium, and sodium carbonate

The equation for the reaction between propanoic acid (C3H6O2), oxygen (O2), potassium (K), and sodium carbonate (Na2CO3) can be written as follows:

2 C3H6O2 + 9 O2 + 4 K + 2 Na2CO3 → 6 CO2 + 4 K2O + 4 Na2O + 6 H2O

This equation represents a balanced chemical reaction, where the number of atoms of each element is the same on both sides of the equation. The coefficients in front of each compound indicate the number of molecules or moles involved in the reaction.

Please note that this equation is a hypothetical example and may not represent an actual reaction. It is always important to consult reliable sources or conduct experiments to verify the accuracy of specific chemical reactions.

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