Question

ДОПОМОЖІТЬ будь ласка 1. Опишіть якісний і кількісний склад молекули за хімічною формулою: Al2O32. Запишіть що означають ці записи 1) 3H2 2) CO2. 3) 4CaSo4 [ приклад: 2O2-дві молекули простої речовини яка складається з двох атомів Оксигену.]3. Обчисліть валентність елементів у їх сполуках з Оксигеном 1) Mg(ll)O 2) Cr(lll)O 3) Si(lV)O. Допоможіть будь ласка​

Answer 1

Molecular Composition of Al2O3:

The chemical formula Al2O3 represents aluminum oxide. It consists of two aluminum (Al) atoms and three oxygen (O) atoms. The subscript numbers in the formula indicate the number of atoms of each element in the molecule. Therefore, Al2O3 has a qualitative composition of 2 aluminum atoms and 3 oxygen atoms [[1]].

Interpretation of Chemical Notations:

1) 3H2: This notation represents three molecules of hydrogen gas (H2). Each molecule of hydrogen gas consists of two hydrogen atoms bonded together [[2]].

2) CO2: This notation represents one molecule of carbon dioxide (CO2). It consists of one carbon atom bonded to two oxygen atoms [[3]].

3) 4CaSO4: This notation represents four molecules of calcium sulfate (CaSO4). Each molecule of calcium sulfate consists of one calcium atom, one sulfur atom, and four oxygen atoms [[4]].

Valency of Elements in Compounds with Oxygen:

1) Mg(ll)O: The Roman numeral (ll) in the notation Mg(ll)O indicates that magnesium (Mg) has a valency of +2 in this compound. Therefore, magnesium forms a divalent cation (Mg2+) when it combines with oxygen (O) to form magnesium oxide (MgO) [[5]].

2) Cr(lll)O: The Roman numeral (lll) in the notation Cr(lll)O indicates that chromium (Cr) has a valency of +3 in this compound. Therefore, chromium forms a trivalent cation (Cr3+) when it combines with oxygen (O) to form chromium oxide (Cr2O3) [[6]].

3) Si(lV)O: The Roman numeral (lV) in the notation Si(lV)O indicates that silicon (Si) has a valency of +4 in this compound. Therefore, silicon forms a tetravalent cation (Si4+) when it combines with oxygen (O) to form silicon oxide (SiO2) [[7]].

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