Question

5. За наведеними скороченими йонно-молекулярними рівняннями реакцій напишіть по два повних йонно-молекулярних рівняння реакцій (користуйтесь таблицею розчинності). Fe3+ + 3OH = Fe(OH)3+ 2H + SO3²- = H2O + SOz ​

Answer 1

Ответ:

будетSO4+BA2+

ВСе

Answer 2

Writing Ionic-Molecular Equations

When writing ionic-molecular equations, it is important to consider the solubility of the compounds involved. To write the full ionic-molecular equations, we need to know the solubility rules. These rules help us determine which compounds are soluble and which ones are insoluble in water.

Unfortunately, I couldn't find a specific table of solubility for the compounds mentioned in your question. However, I can still provide you with an example of how to write ionic-molecular equations using the given reactions.

Example Reactions

1. Fe3+ + 3OH- → Fe(OH)3

In this reaction, Fe3+ ions react with OH- ions to form Fe(OH)3. This is a precipitation reaction because Fe(OH)3 is insoluble in water. The balanced equation for this reaction is:

Fe3+ + 3OH- → Fe(OH)3

2. 2H+ + SO3^2- → H2O + SOz

In this reaction, H+ ions react with SO3^2- ions to form water (H2O) and an unknown compound represented by SOz. Without knowing the specific solubility of SOz, it is difficult to determine whether it is soluble or insoluble. Therefore, we cannot provide a balanced equation without more information.

Please note that the second reaction is not a typical ionic-molecular equation, as it involves the formation of an unknown compound (SOz). Ionic-molecular equations usually involve known compounds with specific solubility properties.

I hope this helps! Let me know if you have any further questions.