Question

ХІМІЯ 11 КЛАС! ДАЮ 50 БАЛЛІВ! ЗА СПАМ - ЖАЛОБА! Скільки за масою (кг) потрібно взяти хлору для одержання 243 кг хлороформу із дихлорметану? → Молярну масу М беремо в кг/моль Який об’єм газу виділиться при горінні 13 г ацетилену?

Answer 1

Calculation of Chlorine Required for Chloroform Production

To calculate the amount of chlorine (Cl2) required to produce 243 kg of chloroform (CHCl3) from dichloromethane (CH2Cl2), we need to consider the balanced chemical equation for the reaction between dichloromethane and chlorine.

The balanced equation for the reaction is as follows:

CH2Cl2 + Cl2 -> CHCl3 + HCl

From the equation, we can see that 1 mole of dichloromethane reacts with 1 mole of chlorine to produce 1 mole of chloroform. Therefore, the stoichiometric ratio between dichloromethane and chlorine is 1:1.

To find the amount of chlorine required, we need to calculate the number of moles of chloroform produced and then convert it to mass using the molar mass of chlorine.

1. Calculate the number of moles of chloroform produced: - The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. - Therefore, the number of moles of chloroform produced is given by: Moles of CHCl3 = Mass of CHCl3 / Molar mass of CHCl3 = 243,000 g / 119.38 g/mol ≈ 2035.8 mol

2. Calculate the number of moles of chlorine required: - Since the stoichiometric ratio between dichloromethane and chlorine is 1:1, the number of moles of chlorine required is also 2035.8 mol.

3. Convert the number of moles of chlorine to mass: - The molar mass of chlorine (Cl2) is approximately 70.90 g/mol. - Therefore, the mass of chlorine required is given by: Mass of Cl2 = Moles of Cl2 * Molar mass of Cl2 = 2035.8 mol * 70.90 g/mol ≈ 144,303.62 g ≈ 144.30 kg

Therefore, approximately 144.30 kg of chlorine is required to produce 243 kg of chloroform from dichloromethane.

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