
Какой объем оксида углерода 4 вступает в реакцию с гидроксидом калия массой 22.4 грамма


Ответы на вопрос

Х л 22,4 г
СO2 + 2 KOH = K2CO3 + H2O
n = 1 моль n = 2 моль
Vm=22,4 л/моль Mr = 56 г/моль
V = 22,4 л m = 112 г
Х л СО2 - 22,4 г КОН
22,4 л СО2 - 112 г КОН
V(CO2) = 22,4 * 22,4 / 112 =4,48 л



Reaction of Carbon Dioxide with Potassium Hydroxide
When carbon dioxide reacts with potassium hydroxide, the following chemical equation represents the reaction:
CO2 + 2KOH → K2CO3 + H2O
This equation shows that one molecule of carbon dioxide reacts with two molecules of potassium hydroxide to produce one molecule of potassium carbonate and one molecule of water.
Calculation of the Volume of Carbon Dioxide
To calculate the volume of carbon dioxide that reacts with 22.4 grams of potassium hydroxide, we can use the concept of molar volume and the stoichiometry of the reaction.
1. Molar Mass of Potassium Hydroxide (KOH): The molar mass of KOH is 56.11 g/mol (39.10 g/mol for K + 16.00 g/mol for O + 1.01 g/mol for H).
2. Moles of Potassium Hydroxide: Using the given mass of 22.4 grams and the molar mass of KOH, we can calculate the moles of KOH: ``` Moles of KOH = Mass of KOH / Molar Mass of KOH = 22.4 g / 56.11 g/mol ≈ 0.399 moles ```
3. Moles of Carbon Dioxide: From the balanced chemical equation, we know that 1 mole of CO2 reacts with 2 moles of KOH. Therefore, the moles of CO2 can be calculated as: ``` Moles of CO2 = 0.399 moles / 2 = 0.1995 moles ```
4. Molar Volume of a Gas at STP: At standard temperature and pressure (STP), the molar volume of a gas is approximately 22.4 liters/mol.
5. Volume of Carbon Dioxide: Using the moles of CO2 and the molar volume at STP, we can calculate the volume of CO2: ``` Volume of CO2 = Moles of CO2 * Molar Volume at STP = 0.1995 moles * 22.4 L/mol ≈ 4.47 liters ```
Therefore, the volume of carbon dioxide that reacts with 22.4 grams of potassium hydroxide is approximately 4.47 liters.


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