
на одну чашку весов положили порцию серы массой 160г. сколько атомов железа должна содержать порция
железа на другой чашке, чтобы весы были в состоянии равновесия?

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Ответ на рисунке
Ответ: 2,85Na атомов




Equilibrium of the Balance Scale
To determine the number of iron atoms needed to achieve equilibrium on the other side of the balance scale, we need to consider the molar masses of sulfur (S) and iron (Fe) and use the concept of molar ratios.
1. Calculate the molar mass of sulfur (S): - The atomic mass of sulfur (S) is approximately 32.06 g/mol.
2. Calculate the molar mass of iron (Fe): - The atomic mass of iron (Fe) is approximately 55.85 g/mol.
3. Calculate the number of moles of sulfur (S) in the given mass: - Mass of sulfur (S) = 160 g - Number of moles of sulfur (S) = (mass of sulfur (S)) / (molar mass of sulfur (S))
4. Determine the molar ratio between iron (Fe) and sulfur (S): - The balanced chemical equation for iron sulfide (FeS) is: Fe + S → FeS - From the equation, we can see that the molar ratio between iron (Fe) and sulfur (S) is 1:1.
5. Calculate the number of moles of iron (Fe) needed: - Number of moles of iron (Fe) = (number of moles of sulfur (S)) * (molar ratio of iron (Fe) to sulfur (S))
6. Calculate the mass of iron (Fe) needed: - Mass of iron (Fe) = (number of moles of iron (Fe)) * (molar mass of iron (Fe))
7. Convert the mass of iron (Fe) to the number of atoms: - Number of atoms of iron (Fe) = (mass of iron (Fe)) / (atomic mass of iron (Fe))
Note: The molar ratio between iron (Fe) and sulfur (S) is 1:1 because the balanced chemical equation for iron sulfide (FeS) shows that one atom of iron combines with one atom of sulfur to form one molecule of iron sulfide.
Please provide the molar mass of sulfur (S) in order to proceed with the calculations.


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