Question

Pb(OH)2 + HNO3 → вкажіть суму коефіцієнтів

Answer 1

Ответ:

PB(OH)2 + 2HNO3 → PB(NO3)2 + 2H2O

2+2=4

Answer 2

The chemical reaction between Pb(OH)2 (lead(II) hydroxide) and HNO3 (nitric acid) is as follows:

Pb(OH)2 + 2HNO3 → Pb(NO3)2 + 2H2O

In this reaction, one molecule of Pb(OH)2 reacts with two molecules of HNO3 to produce one molecule of Pb(NO3)2 and two molecules of H2O.

The coefficients of the reaction represent the number of moles of each reactant needed to produce one mole of each product. In this case, the coefficient of Pb(OH)2 is 1, the coefficient of HNO3 is 2, the coefficient of Pb(NO3)2 is 1, and the coefficient of H2O is 2 .

To balance the equation, we need to ensure that the number of atoms for each element on the reactant side is equal to the number of atoms for the same element on the product side. This is achieved by adjusting the coefficients of the reactants and products.

In this case, the equation is already balanced:

- There is 1 atom of Pb on the reactant side and 1 atom of Pb on the product side. - There are 2 atoms of O on the reactant side (from Pb(OH)2 and HNO3) and 2 atoms of O on the product side (from Pb(NO3)2 and 2H2O). - There are 2 atoms of H on the reactant side (from HNO3 and H2O) and 2 atoms of H on the product side (from H2O and Pb(NO3)2). - There are 2 atoms of N on the reactant side (from HNO3) and 2 atoms of N on the product side (from Pb(NO3)2).

So, the balanced chemical equation is:

Pb(OH)2 + 2HNO3 → Pb(NO3)2 + 2H2O