Question

Cu3C2H2O8>CuO+CO2++H2O​

Answer 1

Ответ:

Надеюсь так, ещё на всякий случай подписала что есть что

Answer 2

The chemical equation you've provided is a balanced chemical equation representing the reaction of copper(III) oxalate (Cu3C2H2O8) with water (H2O).

The equation is:

Cu3C2H2O8 + H2O -> CuO + CO2 + 2H2O

This equation indicates that one molecule of copper(III) oxalate reacts with two molecules of water to produce one molecule of copper(I) oxide (CuO), one molecule of carbon dioxide (CO2), and two molecules of water (H2O).

The reaction can be broken down into the following steps:

1. Copper(III) oxalate (Cu3C2H2O8) reacts with water (H2O) to form copper(I) oxide (CuO) and carbon dioxide (CO2). This is the main reaction that takes place.

2. The copper(I) oxide (CuO) produced in the main reaction is a solid, which means it does not dissolve in water. It is a white powder that is insoluble in water.

3. The carbon dioxide (CO2) produced in the main reaction is a gas, which means it does dissolve in water. It is a colorless, odorless gas that is soluble in water.

4. Two molecules of water (H2O) are produced as a byproduct of the reaction. This is because the balanced chemical equation requires two molecules of water to react with one molecule of copper(III) oxalate.

Please note that the reaction conditions (temperature, pressure, etc.) can affect the rate of reaction and the yield of the products. Also, this reaction is an example of a double displacement reaction, where the cations and anions of two different compounds switch places.

Unfortunately, the source provided does not contain any relevant information for this answer.