Question

Cкладіть молекулярні та йонні рівняння для схем : а) Ca(OH)2 + H2SO4 → ... ; б) Li2SO3 і HNO3 →... ; в) ZnCl2 + Na2SiO3 →.... Завдання виконуєте на ЛИСТКУ, не переписуючи та прикріплюєте файлом. А тут просто напишіть любу букву чи цифру, щоб зарахувалось

Answer 1

Ответ:

Объяснение:

Ca(OH)2 + H2SO4 = CaSO4↓ + 2H2O

Ca(2+) + 2OH(-) + 2H(+) + SO4(2-) = CaSO4↓ + 2H2O

Li2SO3 + 2HNO3 = 2LiNO3 + SO2↑ + H2O

2Li(+) + SO3(2-) + 2H(+) + 2NO3(-) = 2Li(+) + 2NO3(-) + SO2↑ + H2O

SO3(2-) + 2H(+) = SO2↑ + H2O

ZnCL2 + Na2SiO3 = 2NaCl + ZnSiO3↓

Zn(2+) + 2Cl(-) + 2Na(+) + SiO3(2-) =2Na(+)+ 2Cl(-) + ZnSiO3↓

Zn(2+) + SiO3(2-) = ZnSiO3↓

Answer 2

Ответ:

почему это стоит в 1-4классах?

Answer 3

а) Ca(OH)2 + H2SO4 → ...

To write the molecular and ionic equations for the given reaction, we need to first understand the reactants and products involved.

The reactants are: - Calcium hydroxide (Ca(OH)2) - Sulfuric acid (H2SO4)

The products are not provided in the question, so we will assume that a neutralization reaction occurs, resulting in the formation of water (H2O) and a salt.

The balanced molecular equation for the reaction is: Ca(OH)2 + H2SO4 → CaSO4 + 2H2O

To write the ionic equation, we need to break down the reactants and products into their respective ions. In this case, calcium hydroxide dissociates into calcium ions (Ca2+) and hydroxide ions (OH-), while sulfuric acid dissociates into hydrogen ions (H+) and sulfate ions (SO42-).

The ionic equation for the reaction is: Ca2+ + 2OH- + 2H+ + SO42- → CaSO4 + 2H2O

б) Li2SO3 + HNO3 → ...

The reactants for this reaction are: - Lithium sulfite (Li2SO3) - Nitric acid (HNO3)

The products are not provided, so we will assume that a neutralization reaction occurs, resulting in the formation of water (H2O) and a salt.

The balanced molecular equation for the reaction is: Li2SO3 + 2HNO3 → 2LiNO3 + H2O + SO2

To write the ionic equation, we need to break down the reactants and products into their respective ions. In this case, lithium sulfite dissociates into lithium ions (Li+) and sulfite ions (SO32-), while nitric acid dissociates into hydrogen ions (H+) and nitrate ions (NO3-).

The ionic equation for the reaction is: 2Li+ + SO32- + 2H+ + 2NO3- → 2LiNO3 + H2O + SO2

в) ZnCl2 + Na2SiO3 → ...

The reactants for this reaction are: - Zinc chloride (ZnCl2) - Sodium silicate (Na2SiO3)

The products are not provided, so we will assume that a double displacement reaction occurs, resulting in the formation of a precipitate.

The balanced molecular equation for the reaction is: ZnCl2 + Na2SiO3 → ZnSiO3 + 2NaCl

To write the ionic equation, we need to break down the reactants and products into their respective ions. In this case, zinc chloride dissociates into zinc ions (Zn2+) and chloride ions (Cl-), while sodium silicate dissociates into sodium ions (Na+) and silicate ions (SiO32-).

The ionic equation for the reaction is: Zn2+ + 2Cl- + 2Na+ + SiO32- → ZnSiO3 + 2Na+ + 2Cl-

Please note that the provided equations are based on assumptions about the products formed in the reactions. The actual products may vary depending on the reaction conditions.