Question

Складіть молекулярні, повні та скорочені іонні рівняння реакцій між розчинами А) Al(OH)3 + H2SO4 —> Б) гідроксиду барію і нітратної кислоти

Answer 1

Ответ:

Объяснение:

2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O

2Al(OH)3 + 6H(+) + 3SO4(2-) = 2Al(3+) + 3SO4(2-) + 6H2O

2Al(OH)3 + 6H(+) = 2Al(3+) + 6H2O

Ba(OH)2 + 2HNO3 = Ba(NO3)2 + 2H2O

Ba(2+) + 2OH(-) + 2H(+) + 2NO3(-) = Ba(2+) + 2NO3(-) + 2H2O

OH(-) + H(+) = H2O

Answer 2

Molecular Equation:

The molecular equation for the reaction between aluminum hydroxide (Al(OH)3) and sulfuric acid (H2SO4) is:

Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O [[1]]

Ionic Equation:

To write the ionic equation, we need to first break down the reactants and products into their respective ions.

The reactants are: - Aluminum hydroxide (Al(OH)3) dissociates into Al3+ and OH- ions. - Sulfuric acid (H2SO4) dissociates into H+ and SO4^2- ions.

The products are: - Aluminum sulfate (Al2(SO4)3) dissociates into Al3+ and SO4^2- ions. - Water (H2O) does not dissociate.

Therefore, the ionic equation for the reaction is:

3Al^3+ + 3OH- + 3H+ + 3SO4^2- → Al2(SO4)3 + 3H2O [[1]]

Net Ionic Equation:

To write the net ionic equation, we need to eliminate the spectator ions, which are ions that appear on both sides of the equation and do not participate in the actual reaction.

In this case, the spectator ions are the Al^3+ and SO4^2- ions.

The net ionic equation for the reaction between aluminum hydroxide and sulfuric acid is:

3OH- + 3H+ → 3H2O [[1]]

Reaction between Barium Hydroxide and Nitric Acid:

You also mentioned a reaction between barium hydroxide and nitric acid. The molecular equation for this reaction is:

Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O [[2]]

The ionic equation can be written as:

Ba^2+ + 2OH- + 2H+ + 2NO3- → Ba(NO3)2 + 2H2O [[2]]

And the net ionic equation is:

2OH- + 2H+ → 2H2O [[2]]

I hope this helps! Let me know if you have any further questions.