Question

Mr(H3BO3)= ? M(H3BO3)=?

Answer 1

Mr(H3BO3) = 1*3 + 11 + 16*3 =62

Mr(H3BO3) = 62 г/моль

Answer 2

In the chemical compound H3BO3, the chemical formula indicates that it contains one atom of boron (B), three atoms of hydrogen (H), and three atoms of oxygen (O). To determine the molar mass (M) of H3BO3, you can look up the atomic masses of these elements and then sum them up according to the number of atoms in the chemical formula.

The atomic masses are as follows:

• Boron (B) has an atomic mass of approximately 10.81 g/mol.
• Hydrogen (H) has an atomic mass of approximately 1.01 g/mol.
• Oxygen (O) has an atomic mass of approximately 16.00 g/mol.

Now, calculate the molar mass of H3BO3:

Molar mass (H3BO3) = (3 × Molar mass of H) + (1 × Molar mass of B) + (3 × Molar mass of O) Molar mass (H3BO3) = (3 × 1.01 g/mol) + (1 × 10.81 g/mol) + (3 × 16.00 g/mol)

Molar mass (H3BO3) = 3.03 g/mol + 10.81 g/mol + 48.00 g/mol

Molar mass (H3BO3) = 61.84 g/mol

So, the molar mass of H3BO3 is approximately 61.84 grams per mole.