Question

C₂H6→ C₂H₂ → C₂H4 → C₂H6→ C₂H5Br → C₂H4.​

Answer 1

Ответ:

вот на фото все решено

Объяснение:

Answer 2

The sequence of chemical reactions you've mentioned appears to represent a series of transformations involving ethane (C₂H₆), ethylene (C₂H₄), and ethyne (C₂H₂), along with the introduction of bromine (Br₂). Let's break down each step:

1. C₂H₆ (ethane) → C₂H₂ (ethyne): This is a process known as dehydrogenation, where ethane loses two hydrogen atoms to form ethyne (also known as acetylene). The reaction can be represented as follows: C₂H₆ → C₂H₂ + H₂

2. C₂H₂ (ethyne) → C₂H₄ (ethylene): Ethyne can undergo hydrogenation, where it gains two hydrogen atoms to form ethylene. The reaction can be represented as follows: C₂H₂ + H₂ → C₂H₄

3. C₂H₄ (ethylene) → C₂H₆ (ethane): This is the reverse of the first step. Ethylene can undergo hydrogenation to form ethane. The reaction can be represented as follows: C₂H₄ + H₂ → C₂H₆

4. C₂H₆ (ethane) → C₂H₅Br (ethyl bromide): Ethane can react with bromine (Br₂) to form ethyl bromide (C₂H₅Br). This is a substitution reaction where one of the hydrogen atoms in ethane is replaced by a bromine atom. The reaction can be represented as follows: C₂H₆ + Br₂ → C₂H₅Br + HBr

5. C₂H₅Br (ethyl bromide) → C₂H₄ (ethylene): Ethyl bromide can undergo dehydrohalogenation, where it loses a hydrogen atom and a bromine atom to form ethylene. The reaction can be represented as follows: C₂H₅Br → C₂H₄ + HBr

So, the overall sequence of reactions involves the conversion of ethane to ethyne, then to ethylene, back to ethane, then to ethyl bromide, and finally back to ethylene. This sequence demonstrates various types of reactions, including dehydrogenation, hydrogenation, and substitution.