Question

HNO3 + PbS + H₂SO4 →​

Answer 1

PbS+HNO3+H2SO4

S(2-)-2e=>S(0)

NO3(-)+4H(+)+3e=>NO+2H2O

3S(2-)+2NO3(-)+8H(+)=>3S(0)+2NO+4H2O

3PbS+2HNO3+3H2SO4=>3PbSO4+3S+2NO+4H2O

В ходе реакции возможно несколько исходов. Я написал один из них.

Answer 2

The chemical equation you've provided appears to be incomplete. It's missing the products of the reaction. To balance the equation and determine the products, we need more information about the reaction conditions and reactants. However, I can provide a general idea of what might happen when nitric acid (HNO3) reacts with lead sulfide (PbS) in the presence of sulfuric acid (H2SO4).

One possible reaction could be the oxidation of lead sulfide (PbS) by nitric acid (HNO3) to produce lead sulfate (PbSO4), nitrogen dioxide (NO2), and water (H2O):

PbS + 4HNO3 → PbSO4 + 4NO2 + 2H2O

In this reaction, lead sulfide is oxidized to lead sulfate, and nitric acid is reduced to produce nitrogen dioxide gas. Sulfuric acid (H2SO4) may act as a catalyst or provide additional sulfuric ions to the reaction, but it doesn't change the overall chemical equation.

Please note that this is a simplified representation, and the actual reaction may depend on factors such as the concentration of the acids and the reaction conditions. Safety precautions should be taken when working with concentrated acids and lead compounds, as they can be hazardous.