Question

Нейтрализация 2,45г кислоты израсходовали 2г гидроксид натрия. Определите молярную массу эквивалента кислоты

Answer 1

Получается 4 альтернатива 3,9

Answer 2

To determine the molar mass of the acid equivalent, we need to first find the number of moles of the acid and the number of moles of the sodium hydroxide used in the neutralization reaction. Then, we can calculate the molar mass of the acid equivalent.

Given: Mass of acid (H2SO4) = 2.45 g Mass of sodium hydroxide (NaOH) used = 2 g

Step 1: Write the balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH):

H2SO4 + 2NaOH -> Na2SO4 + 2H2O

Step 2: Calculate the number of moles of sodium hydroxide used:

Molar mass of NaOH = 23.0 g/mol (Na) + 16.0 g/mol (O) + 1.0 g/mol (H) = 40.0 g/mol

Number of moles of NaOH = Mass of NaOH used / Molar mass of NaOH Number of moles of NaOH = 2 g / 40.0 g/mol = 0.05 mol

Step 3: Determine the number of moles of sulfuric acid (H2SO4) used based on the stoichiometry of the balanced chemical equation:

From the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.

Number of moles of H2SO4 = 0.05 mol (Since the reaction is 1:2)

Step 4: Calculate the molar mass of the acid (H2SO4):

Molar mass of H2SO4 = 2(1.0 g/mol H) + 32.1 g/mol S + 4(16.0 g/mol O) = 98.1 g/mol

Step 5: Determine the molar mass of the acid equivalent (1 mole of H2SO4):

The molar mass of the acid equivalent is the same as the molar mass of the acid (H2SO4):

Molar mass of the acid equivalent = 98.1 g/mol

So, the molar mass of the acid equivalent is approximately 98.1 g/mol.