Question

Найти массу 0,2 моль mgso4

Answer 1

M(MgSO4)=120г/моль

m(MgSO4)=120*0,2=24 г

Answer 2

To find the mass of 0.2 moles of MgSO4 (magnesium sulfate), you'll need to use the molar mass of MgSO4. First, let's find the molar mass of magnesium sulfate (MgSO4):

Mg (Magnesium) atomic mass = 24.305 g/mol S (Sulfur) atomic mass = 32.06 g/mol O (Oxygen) atomic mass = 16.00 g/mol

Molar mass of MgSO4: Mg: 1 atom * 24.305 g/mol = 24.305 g/mol S: 1 atom * 32.06 g/mol = 32.06 g/mol O: 4 atoms * 16.00 g/mol = 64.00 g/mol

Molar mass of MgSO4 = 24.305 + 32.06 + 64.00 = 120.365 g/mol

Now, to find the mass of 0.2 moles of MgSO4, you can use the formula:

Mass = Number of moles * Molar mass

Mass = 0.2 moles * 120.365 g/mol ≈ 24.07 grams

So, the mass of 0.2 moles of MgSO4 is approximately 24.07 grams.