Question

A) CH3COOH +CaO-B) CH3COOH +KoH-Sos

Answer 1

2CH3COOH + CaO = (CH3COO)2Ca + H2O

CH3COOH + KOH = CH3COOK + H2O

Answer 2

It appears that you have provided two chemical reactions involving acetic acid (CH3COOH) with different reactants. Let's examine each reaction:

A) CH3COOH + CaO: The reaction between acetic acid and calcium oxide (CaO) can be represented as follows:

CH3COOH + CaO -> Ca(CH3COO)2 + H2O

In this reaction, acetic acid (CH3COOH) reacts with calcium oxide (CaO) to form calcium acetate (Ca(CH3COO)2) and water (H2O).

B) CH3COOH + KOH: The reaction between acetic acid and potassium hydroxide (KOH) can be represented as follows:

CH3COOH + KOH -> CH3COOK + H2O

In this reaction, acetic acid (CH3COOH) reacts with potassium hydroxide (KOH) to form potassium acetate (CH3COOK) and water (H2O).

Both of these reactions involve the neutralization of acetic acid with a base. In reaction A, calcium oxide (CaO) acts as the base, while in reaction B, potassium hydroxide (KOH) acts as the base. The products formed in each reaction are a salt (calcium acetate or potassium acetate) and water.