Question

Cucl2-cuso4-cu(oh) 2-cuo​

Answer 1

1)CuCl2+H2SO4=CuSO4+2HCl

2)CuSO4+2NaOH=Cu(OH)2+Na2SO4

3)Cu(OH)2=CuO+H2O

Answer 2

The chemical equation you provided appears to show a series of reactions involving copper(II) chloride (CuCl2), copper(II) sulfate (CuSO4), copper(II) hydroxide (Cu(OH)2), and copper(II) oxide (CuO). Let's break down the reactions step by step:

1. CuCl2 (copper(II) chloride) reacts with CuSO4 (copper(II) sulfate) to form Cu2Cl2(SO4)2:

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CuCl2 + CuSO4 → Cu2Cl2(SO4)2

2. Cu2Cl2(SO4)2 is a complex compound, and we can further decompose it in water:

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Cu2Cl2(SO4)2 + H2O → Cu(OH)2 + 2HCl + H2SO4

In this reaction, copper(II) chloride sulfate decomposes into copper(II) hydroxide, hydrogen chloride, and sulfuric acid.

3. Cu(OH)2 (copper(II) hydroxide) can undergo thermal decomposition to form CuO (copper(II) oxide):

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Cu(OH)2 → CuO + H2O

Here, copper(II) hydroxide breaks down into copper(II) oxide and water.

So, the overall reaction from the initial reactants CuCl2 and CuSO4 to the final product CuO can be represented as follows:

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CuCl2 + CuSO4 + H2O → CuO + 2HCl + H2SO4

Keep in mind that chemical reactions can often be influenced by factors such as temperature, pressure, and concentration. If you plan to carry out these reactions in a laboratory setting, it's essential to take proper safety precautions and have a good understanding of the specific reaction conditions.