Question

P->P2O5->H3PO4 Na->Na2O->NaOH

Answer 1

4P + 5O2 = 2P2O5

P2O5 + 3H2O = 2H3PO4

4Na + O2 = 2Na2O

Na2O + H2O = 2NaOH

Answer 2

Ответ:

Объяснение:

4P + 5O2 = 2P2O5 ( оксид фосфора(5))

P2O5 + 3H2O = 2H3PO4 ( фосфорная кислота)

4Na + O2 =2 Na2O ( оксид натрия)

Na2O + H2O = 2NaOH (гидроксид натрия)

Answer 3

The series of chemical reactions you've provided involves the conversion of phosphorus (P) to phosphoric acid (H3PO4) and sodium (Na) to sodium hydroxide (NaOH). Here's a breakdown of the reactions:

1. P -> P2O5: Phosphorus (P) reacts with oxygen (O2) to form diphosphorus pentoxide (P2O5). This reaction represents the combustion of phosphorus, which results in the formation of an oxide.

2. P2O5 -> H3PO4: Diphosphorus pentoxide (P2O5) reacts with water (H2O) to produce phosphoric acid (H3PO4). This is an example of an acid-base reaction, where the oxide reacts with water to form an acid.

3. Na -> Na2O: Sodium (Na) reacts with oxygen (O2) to form sodium oxide (Na2O). This reaction represents the combustion of sodium, which results in the formation of an oxide.

4. Na2O -> NaOH: Sodium oxide (Na2O) reacts with water (H2O) to produce sodium hydroxide (NaOH). This is an example of an acid-base reaction, where the oxide reacts with water to form a base.

Overall, these reactions demonstrate the transformation of phosphorus and sodium into their respective oxides, followed by the reaction of the oxides with water to produce phosphoric acid and sodium hydroxide.