Question

Na2Co3+Hce > NaCe+H2O+Co2

Answer 1

Объяснение:

Na2CO3 + 2HCl → 2NaCl + H2O + CO2↑

полное ионное: 2Na(+) + CO3(2-) + 2H(+) + 2Cl(-) → 2Na(+) + 2Cl(-) + H2O + CO2↑

сокращенное ионное: CO3(2-) + 2H(+) → H2O + CO2↑

Answer 2

The chemical equation you provided appears to be unbalanced. Let's balance it:

Na2CO3 + HCe → NaCe + H2O + CO2

To balance the equation, we need the same number of atoms of each element on both sides. Here's the balanced equation:

2 Na2CO3 + 2 HCe → 2 NaCe + 3 H2O + 2 CO2

Now, the equation is balanced. It shows that when sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCe), it forms sodium cerium (NaCe), water (H2O), and carbon dioxide (CO2).